Total Displacement of a Bee's Flight

What is the total displacement of a bee that flies 2 meters east, 5 meters north, and 3 meters east? Group of answer choices

None of the above.

5 meters

5 meters east

5meters east and 5 meters north

To find the total displacement of the bee, we can break down its movements into components and then calculate the resultant vector.

1. The bee flies 2 meters east.
2. Then it flies 5 meters north.
3. Finally, it flies 3 meters east.

Now, let's sum the movements in each direction:

• Total eastward movement: (2 \text{ meters} + 3 \text{ meters} = 5 \text{ meters east})
• Total northward movement: (5 \text{ meters north})

Now we can represent the total displacement as a vector:

• Displacement = (5 \text{ meters east} + 5 \text{ meters north})

To find the magnitude of the total displacement, we can use the Pythagorean theorem:

[ \text{Displacement} = \sqrt{(5 \text{ meters})^2 + (5 \text{ meters})^2} = \sqrt{25 + 25} = \sqrt{50} \approx 7.07 \text{ meters} ]

However, since the question asks for the total displacement in terms of direction, we can say:

The total displacement is (5 \text{ meters east and } 5 \text{ meters north}).

Thus, the correct answer is:

5 meters east and 5 meters north.