Pebble Velocity After 3 Seconds of Free Fall

How fast will a pebble be traveling 3 seconds after being dropped? Group of answer choices

9.8 m/s2

29.4 m/s

-9.8 m/s

-29.4 m/s

When a pebble is dropped, it is subject to the acceleration due to gravity, which is approximately (9.8 , \text{m/s}^2) downward. To find the velocity of the pebble after 3 seconds, you can use the formula for velocity under constant acceleration:

[ v = u + at ]

where:

• ( v ) is the final velocity,
• ( u ) is the initial velocity (0 m/s, since the pebble is dropped),
• ( a ) is the acceleration due to gravity ((9.8 , \text{m/s}^2)),
• ( t ) is the time (3 seconds).

Plugging in the values:

[ v = 0 + (9.8 , \text{m/s}^2)(3 , \text{s}) = 29.4 , \text{m/s} ]

So, the pebble will be traveling at (29.4 , \text{m/s}) downward after 3 seconds. The correct answer is:

29.4 m/s