Free-Fall Speed After 1 and 2 Seconds

Consider a 10 kg object free-falling from a cliff with an initial velocity of 0 m/sec. How fast will the object be traveling after 1 second and after 2 seconds? Group of answer choices

9.8 m/sec after 1 second and 29.4 m/sec after 2 seconds

19.6 m/sec after 1 second and 29.4 m/sec after 2 seconds

9.8 m/sec after 1 second and 19.6 m/sec after 2 seconds

9.8 m/sec after 1 and 2 seconds

To determine the speed of a free-falling object under the influence of gravity, we can use the formula for the velocity of an object in free fall:

[ v = v_0 + g \cdot t ]

where:

• ( v ) is the final velocity,
• ( v_0 ) is the initial velocity (0 m/s in this case),
• ( g ) is the acceleration due to gravity (approximately ( 9.8 , \text{m/s}^2 )),
• ( t ) is the time in seconds.

1. After 1 second: [ v = 0 + 9.8 \cdot 1 = 9.8 , \text{m/s} ]

2. After 2 seconds: [ v = 0 + 9.8 \cdot 2 = 19.6 , \text{m/s} ]

So, the object will be traveling at 9.8 m/s after 1 second and 19.6 m/s after 2 seconds.

The correct answer is: **9.8 m/sec after 1 second and 19.6 m/sec after 2 seconds