A marble dropped from a bridge and strike the water in exactly 3 seconds. How high is the bridge? Group of answer choices
44.1 sec
4.1 m
44.1 m
0.41 m
To find the height of the bridge from which the marble was dropped, we can use the formula for the distance fallen under the influence of gravity:
[ d = \frac{1}{2} g t^2 ]
where:
Plugging in the values:
[ d = \frac{1}{2} \times 9.81 , \text{m/s}^2 \times (3 , \text{s})^2 ] [ d = \frac{1}{2} \times 9.81 \times 9 ] [ d = \frac{1}{2} \times 88.29 ] [ d = 44.145 , \text{m} ]
Rounding to one decimal place, the height of the bridge is approximately ( 44.1 , \text{m} ).
So, the correct answer is 44.1 m.