Transformations of Quadrilateral KRWB

Quadrilateral KRWB is shown on the coordinate grid.

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Apply the sequence of transformations below to quadrilateral KRWB .

(x,y) →(x+3, y−7) to get K'R'W'B' (x,y) →(−x,−y) to get K''R''W''B'' and (x,y) →(2x,2y) to get K'''R'''W'''B''' What are the coordinates of K''' ?

( , )

To find the coordinates of ( K''' ) after applying the given transformations to quadrilateral ( KRWB ), we will follow the transformations step by step.

1. Initial Coordinates of K: Let's assume the coordinates of point ( K ) are ( (x, y) ). Since the specific coordinates of ( K ) are not provided in your question, I will denote them as ( (x_K, y_K) ).

2. First Transformation: [ (x, y) \rightarrow (x + 3, y - 7) ] Applying this transformation to ( K ): [ K' = (x_K + 3, y_K - 7) ]

3. Second Transformation: [ (x, y) \rightarrow (-x, -y) ] Applying this transformation to ( K' ): [ K'' = (-(x_K + 3), -(y_K - 7)) = (-x_K - 3, -y_K + 7) ]

4. Third Transformation: [ (x, y) \rightarrow (2x, 2y) ] Applying this transformation to ( K'' ): [ K''' = (2(-x_K - 3), 2(-y_K + 7)) = (-2x_K - 6, -2y_K + 14) ]

Thus, the coordinates of ( K''' ) are: [ (-2x_K - 6, -2y_K + 14) ]

To provide the exact coordinates, you would need to substitute the specific values of ( x_K ) and ( y_K ) from the original coordinates of point ( K ). If you provide those coordinates, I can give you the final answer.